# How do you solve (5q^2)/6-q^2/3=72?

Oct 27, 2016

$q = \pm 12$

#### Explanation:

The objective is to have only one $q$

notice that ${q}^{2}$ is in both numerators so factor that out

${q}^{2} \left(\frac{5}{6} - \frac{1}{3}\right) = 72$

${q}^{2} \left(\frac{5}{6} - \frac{2}{6}\right) = 72$

${q}^{2} \left(\frac{{\cancel{3}}^{1}}{{\cancel{6}}^{2}}\right) = 72 \text{ "->" } {q}^{2} / 2 = 72$

${q}^{2} = 2 \times 72 = 144$

$\sqrt{{q}^{2}} = \sqrt{144}$

$q = \pm 12$
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Footnote

$\left(- 12\right) \times \left(- 12\right) = + 144$

$\left(+ 12\right) \times \left(+ 12\right) = + 144$