How do you solve #5r^2 - 44r + 120 = -30 + 11r# by factoring? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Sudip Sinha Aug 9, 2015 Answer: # r = 5, 6 # Explanation: # 5 r^2 - 44 r + 120 = -30 + 11 r # # => 5 r^2 - 55 r + 150 = 0 # (Adding # 30 - 11 r # to both sides) # => r^2 - 11 r + 30 = 0 # (Dividing by 5) # => r^2 - 5 r - 6 r + 30 = 0 # (Noting that # 30 = 5 * 6 #, and that # 5 + 6 = 11 #) # => r ( r - 5 ) - 6 ( r - 5 ) = 0 # # => ( r - 5 ) ( r - 6 ) = 0 # # => r = 5 # or # r = 6 # Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1298 views around the world You can reuse this answer Creative Commons License