# How do you solve #5t^2=25t#?

##### 1 Answer

Jan 12, 2017

#### Answer:

#### Explanation:

Collect terms on left side of equation thus equating to zero.

subtract 25t from both sides.

#5t^2-25t=cancel(25t)cancel(-25t)#

#rArr5t^2-25t=0# Take out a common factor of 5t

#5t(t-5)=0# We now have a product of factors equal to zero.

#"Thus " 5t=0rArrt=0#

#"or " t-5=0rArrt=5#