# How do you solve 5x+15+4x-3=-2x+4+2?

Mar 25, 2016

$x = - \frac{6}{11}$

#### Explanation:

$1$. Start by simplifying the left side of the equation.

$5 x + 15 + 4 x - 3 = - 2 x + 4 + 2$

$9 x + 12 = - 2 x + 6$

$2$. Add $2 x$ to both sides of the equation to get rid of $- 2 x$ on the right side of the equation so that all terms with the variable, $x$, are on the left side of the equation.

$9 x$ $\textcolor{red}{+ 2 x} + 12 = - 2 x$ $\textcolor{red}{+ 2 x} + 6$

$11 x + 12 = \textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{0} + 6$

$11 x + 12 = 6$

$3$. Subtract $12$ from both sides of the equation to get rid of $12$ on the left side of the equation so that all constant terms are on the right side of the equation.

$11 x + 12$ $\textcolor{red}{- 12} = 6$ $\textcolor{red}{- 12}$

$11 x + \textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{0} = - 6$

$11 x = - 6$

$4$. Divide both sides by 11 to isolate for $x$.

$\textcolor{red}{\frac{\textcolor{b l a c k}{11 x}}{11}} = \textcolor{red}{\frac{\textcolor{b l a c k}{- 6}}{11}}$

color(red)((color(blue)cancelcolor(black)(11)color(black)x)/color(blue)cancelcolor(red)(11)color(black)=color(red)(color(black)(-6)/11)

$\textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} x = - \frac{6}{11} \textcolor{w h i t e}{\frac{a}{a}} |}}}$