Question

How do you solve `5x+15+4x-3=-2x+4+2`?

Answer 1

`x=-6/11`

Explanation:

`1`. Start by simplifying the left side of the equation.

`5x+15+4x-3=-2x+4+2`

`9x+12=-2x+6`

`2`. Add `2x` to both sides of the equation to get rid of `-2x` on the right side of the equation so that all terms with the variable, `x`, are on the left side of the equation.

`9x` `color(red)(+2x)+12=-2x` `color(red)(+2x)+6`

`11x+12=color(darkorange)0+6`

`11x+12=6`

`3`. Subtract `12` from both sides of the equation to get rid of `12` on the left side of the equation so that all constant terms are on the right side of the equation.

`11x+12` `color(red)(-12)=6` `color(red)(-12)`

`11x+color(darkorange)0=-6`

`11x=-6`

`4`. Divide both sides by 11 to isolate for `x`.

`color(red)((color(black)(11x))/11)=color(red)(color(black)(-6)/11)`

`color(red)((color(blue)cancelcolor(black)(11)color(black)x)/color(blue)cancelcolor(red)(11)color(black)=color(red)(color(black)(-6)/11)`

`color(green)(|bar(ul(color(white)(a/a)x=-6/11color(white)(a/a)|)))`