How do you solve # 5x^2 - 12x + 10 = x^2 + 10x#?
4 and 5
Use the new Transforming Method (Google, Yahoo).
Factor pairs of (ac = 40) --> (2, 20). This sum is 22 = -b.
Therefor, the 2 real roots of y' are: y1 = 2 and y2 = 20.
Back to original equation y, the 2 real roots are:
There is no need to factor by grouping and solving the 2 binomials.