How do you solve #5x^2 - 245 = 0 #? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer BRIAN M. Feb 25, 2016 #x=7# or #x=-7# Explanation: #5x^2 - 245 = 0# #5x^2 - 245 + 245 = 0 + 245# to isolate the variable term (x) #5x^2 = 245# #(5x^2)/5 = 245/5# to isolate the #x^2# #x^2 = 49# #x = sqrt49# to eliminate the #x^2# #x=7# or #x=-7# the square can be plus or minus Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2844 views around the world You can reuse this answer Creative Commons License