How do you solve #5x^2-2x-6=-3x^2+6x#?

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Answer 1 · 2017-06-27T10:17:01

#x=-1/2#, or #x=1/2#

First, let's add #3x^2# to both sides

#8x^2-2x-6=6x#

Then, subtract #6x# from both sides

#8x^2-8x-6=0#

Divide the entire equation by #2#

#4x^2-4x-3=0#

Factorise

#(2x+1)(2x-3)=0#

Set each factor equal to #0#

#2x+1=0#
#2x=-1#

#x=-1/2#

#2x-3=0#
#2x=3#
#x=1/2#

Here is the graph

graph{4x^2-4x-3 [-3.08, 3.08, -1.54, 1.54]}