How do you solve 5x ^ { 2} + 40x + 75= 0?

May 19, 2017

$x = \left\{- 3 , - 5\right\}$

Explanation:

You could simply the equation by factoring out a $5$ in each term.

$5 \left({x}^{2} + 8 x + 15\right) = 0$

Dividing both sides by $5$ gives

${x}^{2} + 8 x + 15 = 0$

Factoring...

$\left(x + 3\right) \cdot \left(x + 5\right) = 0$

So

$x = \left\{- 3 , - 5\right\}$