# How do you solve 5x^2-40x+80=0?

May 12, 2016

I think the answer is -5.3.

#### Explanation:

$5 {x}^{2} - 40 x + 80 = 0$

$5 x \cdot 5 x = 25 x$ Take care of the exponent first.

$25 x - 40 x + 80 = 0$ Solve the like terms.

$- 15 x + 80 = 0$ Carry 80 over.

$- 15 \frac{x}{-} 15 = \frac{80}{-} 15$ Cancel out -15 and divide 80 by that same number.

$x = - 5.3$ Plug in the answer you get and round it to the nearest ten.