# How do you solve 5x^2 = –45x?

Jul 1, 2015

$x = - 9$or $x = 0$

#### Explanation:

$T h e$ $a b o v e$ $e q u a t i o n$
$5 {x}^{2} = - 45 x$
Do not divide both sides by $x$. You will lose an answer.
Instead, get both terms on one side and factor:
$5 {x}^{2} + 45 x = 0$

now we got,
$5 x \left(x + 9\right) = 0$

So,

Either $5 x = 0$ or $x + 9 = 0$

Either $x = 0$ or $x = - 9$.