Question

How do you solve `5x^2-8x=6` using the quadratic formula?

Answer 1

`x=(4+-sqrt46)/5`

Explanation:

`5x^2-8x=6`
`5x^2-8x-6=0`

Remember the general form of an equation is `ax^2+bx+c=0` where a,b and c are constants.
Using the quadratic formula.
`x=(-b+-sqrt(b^2-4ac))/(2a)`

`x=(8+-sqrt(64+120))/(2times5)`

`x=(8+-sqrt184)/10`

`x=(8+-2sqrt46)/10`

`x=(4+-sqrt46)/5`