How do you solve #5x + 4y = 2# and #3x - 4y = 14#?

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Answer 1 · 2015-08-02T14:00:06

The solution for the system of equations is
#color(blue)(x=2,y=-2#

Upon adding the two equations we can eliminate #color(blue)(4y)#

#5x+color(blue)(cancel4y)=2 # .....equation #(1)#
# 3x−color(blue)(cancel4y)=14# .....equation #(2)#

#8x=16#
#color(blue)(x=2#

Substituting the value of #x# in the first equation to find #y#
#5x+4y=2 #

#5 * (2)+4y=2 #

#10 +4y=2 #

#4y=-8 #
#color(blue)(y=-2 #