How do you solve #5x + 7= \frac { 3} { 2} x + 63#?

Question

1463 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-04T18:39:22

#x=16#

#5x+7=3/2x+63#

#:.10/2x-3/2x=63-7#

#:.7/2x=56#

multiply L.HS. and R.H.S. by #color(blue) 2#

#:.color(blue)cancel2 xx 7/cancel2x=56 xx color(blue)2#

#:.7x=112#

#:.color(blue)(x=16#

check:

substitute #x=color(blue)16#

#color(blue)5(color(blue)16)+7=3/2(color(blue)16)+63#

#:.80+7=48/2+63#

#:.87=24+63#

#:.87=87#