Question

How do you solve `5x+8y=28` and `-8+y=38` using substitution?

Answer 1

`(x,y)to(-68,46)`

Explanation:

`5x+8y=28to(1)`

`-8+y=38to(2)`

`"simplify equation "(2)" by adding 8 to both sides"`

`y=38+8=46`

`"substitute "y=46" into equation "(1)`

`5x+(8xx46)=28`

`5x+368=28`

`"subtract 368 from both sides"`

`5x=28-368=-340`

`"divide both sides by 5"`

`x=(-340)/5=-68`

`"solution is "(x,y)to(-68,46)`