# How do you solve #5x+8y=28# and #-8+y=38# using substitution?

##### 1 Answer

Jul 12, 2018

#### Answer:

#### Explanation:

#5x+8y=28to(1)#

#-8+y=38to(2)#

#"simplify equation "(2)" by adding 8 to both sides"#

#y=38+8=46#

#"substitute "y=46" into equation "(1)#

#5x+(8xx46)=28#

#5x+368=28#

#"subtract 368 from both sides"#

#5x=28-368=-340#

#"divide both sides by 5"#

#x=(-340)/5=-68#

#"solution is "(x,y)to(-68,46)#