How do you solve #-5x \leq - 8x + 21#?

1 Answer
Jim G.
Jan 3, 2017

#x<=7#

Explanation:

Collect terms in x on the left side of the inequality.

add 8x to both sides.

#-5x+8x<=cancel(-8x)cancel(+8x)+21#

#rArr3x<=21#

To solve for x, divide both sides by 3

#(cancel(3) x)/cancel(3)<=21/3#

#rArrx<=7" is the solution"#

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