How do you solve #5y^2=30y#?

2 Answers
Jul 14, 2018

Answer:

#y=0# or #y=6#

Explanation:

Writing your equation in the form
#5y(y-6)=0#
so we get

#y=0# or #y=6#

Jul 14, 2018

Answer:

#y=0# and #y=6#

Explanation:

We have a second-degree term, so this is beginning to look like a quadratic. Let's subtract #30y# from both sides to find the zeroes:

#5y^2-30y=0#

We can factor a #5y# out, and we get

#5y(y-6)=0#

Setting both factors equal to zero, we get

#y=0# and #y=6#

Hope this helps!