How do you solve #6/(11v)+6/v=1#?

1 Answer
Feb 16, 2016

Answer:

#v=72/11 -> 6 6/11#

Explanation:

Given:#" "6/(11v)+6/v=1#

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Write as:#" " 1/v(6/11+66/11)=1#

#1/v (72/11)=1/1" "#

#color(brown)("note that "1/1" is another way of writing 1 . I did this so ")#
#color(brown)("that you did not have any mental blocks about inverting 1")#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Turn everything upside down!")#

#v(11/72)=1#

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#color(blue)("To get rid of "11/72" on the left hand side multiply "underline("both sides")" by "color(magenta)(72/11))#

#color(brown)("To get rid of something in 'multiply or divide' turn it into 1")#

#vxx11/72color(magenta)(xx72/11)=1color(magenta)(xx72/11)#

#vxx11/11 xx 72/72=72/11#

#color(brown)("But "11/11" and "72/72" both equal to 1")#

#vxx1xx1=72/11#

#v=72/11 -> 6 6/11#