# How do you solve 6 ÷ 3(2 + 1)?

Sep 11, 2015

6

#### Explanation:

Carry out the operation in parentheses first

$\left(\frac{6}{3}\right) \left(3\right)$

Now where people sometimes make a mistake is to multiply

$3$ by $3$

Do not do this.

Write

$\left(\frac{6}{1}\right) \left(\frac{1}{3}\right) \left(3\right)$

Now multiply from left to right

$2 \left(3\right) = 6$

If the problem was $\frac{6}{\left(3 \left(2 + 1\right)\right)}$ then the answer would be different.

This would give

$\frac{6}{\left(3 \left(3\right)\right)} = \frac{6}{9} = \frac{2}{3}$

This is not what the poster has written

What the poster has asked is
$\frac{6}{3} \left(2 + 1\right)$ The parentheses make a difference