How do you solve #6( m - 2) + 14= 3( m + 2) - 10#?

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Answer 1 · 2018-04-08T10:17:17

#m=2/3#

Expand the brackets on both sides:

#6m-12+14=3m+6-10#

Take away the #3m# from the right side of the equation:

#3m-12+14=+6-10#

Work out additions and subtractions:

#3m+2=+4#

Take away the #+2#:

#3m=2#

Divide both sides by #3#:

#(3m)/3=2/3#

So:

#m=2/3#

Answer 2 · 2018-04-08T10:30:10

m=2/3

So we just multiply the number before the bracket with all the numbers in the bracket. Simple algebra.

#6(m-2)+14=3(m+2)-10#
#6m-12+14=3m+6-10#
#3m -12 +14 =6 - 10#
#3m =-6+10 +12 -14#
#3m=22-20 = 3m=2#
#(3m)/3 =2/3#
#m = 2/3#