How do you solve 6( t - 3) = 2( 9k-2t )?

1 Answer
Feb 8, 2017

k = 5/9t - 1 or t = 9/5k + 9/5

Explanation:

6(t-3) = 2(9k-2t)
3(t-3) = 9k - 2
3t - 9 = 9k - 2t
5t - 9 = 9k

Therefore:
k = 5/9t - 1 or t = 9/5k + 9/5