Question

How do you solve `6 (x + 1) - 5 = x + 31`?

Answer 1

`x=6`

Explanation:

`" the first step is to distribute the bracket"`

`6x+6-5=x+31`

`"simplifying left side"`

`6x+1=x+31`

`"subtract x from both sides"`

`6x-x+1=cancel(x)cancel(-x)+31`

`rArr5x+1=31`

`"subtract 1 from both sides"`

`5xcancel(+1)cancel(-1)=31-1`

`rArr5x=30`

`"divide both sides by 5"`

`(cancel(5) x)/cancel(5)=30/5`

`rArrx=6`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left side "=6(6+1)-5=42-5=37`

`"right side "=6+31=37`

`rArrx=6" is the solution"`