How do you solve #6/x+3=12/x#?

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Answer 1 · 2016-11-09T22:35:53

#x = 2#

Step 1) Multiply each side of the equation by #x# to eliminate the fraction and to keep the equation balanced:

#x(6/x + 3) = x(12/x)#

#6 + 3x = 12#

Step 2) Solve for #x# while keeping the equation balanced:

#6 + 3x - 6 = 12 - 6#

#3x = 6#

#(3x)/3 = 6/3#

#x = 2#