# How do you solve 6(x+3)+38=2?

Jun 6, 2016

color(green)(x = -9

#### Explanation:

As we need to find the value of $x$, we try to transpose all the other terms to the right hand side.

Transposing 38 to the right hand side, we get:

$6 \left(x + 3\right) = 2 - 38$

$6 \left(x + 3\right) = - 36$

To eliminate 6, we can divide both sides by 6

$\frac{\cancel{6} \left(x + 3\right)}{\cancel{6}} = - \frac{36}{6}$

$x + 3 = - 6$

Transposing 3 to the right hand side, we get

$x = - 6 - 3$

color(green)(x = -9

Test:
Try substituting the value of $x$ in the original equation and check if it's satisfied