How do you solve $60 x + 1, 200 = 50 (40 + x)$ $60x+ 1,200 = 50 (40+x)$ ?

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Answer 1 · 2016-03-11T08:36:10

$x = 80$ $x = 80$

$60 x + 1200 = 50 (40 + x)$ $60x + 1200 = 50(40 + x)$

To simplify first divide through by 10
$6 x + 120 - 5 (40 + x)$ $6x +120 - 5(40 + x)$

$6 x + 120 = 200 + 5 x$ $6x + 120 = 200 +5x$
$6 x - 5 x = 200 - 120$ $6x - 5x = 200 - 120$

$x = 80$ $x = 80$

How do you solve 60x+1,200=50(40+x)60x+ 1,200 = 50 (40+x)?