# How do you solve 64x + 2( - 9- 7) = 32?

##### 2 Answers
Nov 9, 2016

$x = 1$

#### Explanation:

$64 x + 2 \left(- 9 - 7\right) = 32$

$64 x + 2 \left(- 16\right) = 32 \to$ the $9$ and $7$ are both negatives, which caused the $- 16$.

$64 x - 32 = 32 \to$ the $2$ and $- 16$ were multiplied to create $- 32$

$64 x = 64 \to$ the $- 32$ was added to the right to create $64$.

$x = 1$

In order to make sure it all makes sense, plug in the $1$ for $x$, and see if it all equals $32$ on both sides.

$64 \left(1\right) + 2 \left(- 9 - 7\right) = 32$

$64 + 2 \left(- 16\right) = 32$

$64 - 32 = 32$

$32 = 32$

It all seems to check out perfectly fine.

Nov 9, 2016

$x = 1$

#### Explanation:

$64 x + 2 \left(- 9 - 7\right) = 32$

First, simplify the bracketed terms:

$64 x + 2 x \left(- 16\right) = 32$

Then multiply out the left side:

$64 x - 32 x = 32$

Simplify addition and subtraction:

$32 x = 32$

Therefore,

$x = 1$