How do you solve #66 + 8 log x = 50#?

Question

1095 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-19T23:19:39

#x=1/100#

Subtract #66# from both sides.

#8logx=-16#

Divide both sides by #8#.

#logx=-2#

Recall that #logx=log_10x#.

#log_10x=-2#.

Exponentiate both sides to undo the logarithm.

#10^(log_10x)=10^-2#

#x=10^-2#

#x=1/10^2=1/100#