How do you solve #6c-8-2c=-16#?

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Answer 1 · 2016-12-18T13:27:45

#c = -2#

First group and combine the like terms on the left side of the equation:

#6c - 2c - 8 = -16#

#(6 - 2)c - 8 = -16#

#4c - 8 = -16#

Next, isolate the #c# terms on one side of the equation and the constants on the other side of the equation:

#4c - 8 color(red)( + 8) = -16 color(red)( + 8)#

#4c - 0 = -8#

#4c = -8#

Now we can solve for #c# while keeping the equation balanced:

#(4c)/(color(red)(4)) = -8/(color(red)(4)) #

#(color(red)(cancel(color(black)(4)))c)/color(red)(cancel(color(black)(4))) = -2#

#c = -2#