# How do you solve 6c-8-2c=-16?

Dec 18, 2016

$c = - 2$

#### Explanation:

First group and combine the like terms on the left side of the equation:

$6 c - 2 c - 8 = - 16$

$\left(6 - 2\right) c - 8 = - 16$

$4 c - 8 = - 16$

Next, isolate the $c$ terms on one side of the equation and the constants on the other side of the equation:

$4 c - 8 \textcolor{red}{+ 8} = - 16 \textcolor{red}{+ 8}$

$4 c - 0 = - 8$

$4 c = - 8$

Now we can solve for $c$ while keeping the equation balanced:

$\frac{4 c}{\textcolor{red}{4}} = - \frac{8}{\textcolor{red}{4}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}} c}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} = - 2$

$c = - 2$