How do you solve #(6h-5)(6h+5)=0#?

2 Answers
Apr 23, 2018

Answer:

#h= 5/6# or #h=-5/6#

Explanation:

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#(6h - 5)(6h + 5) = 0#

#6h-5 = 0# or # 6h + 5 = 0#

#h= 5/6# or #h=-5/6#

Apr 23, 2018

Answer:

#h = 5/6, -5/6#

Explanation:

From the null factor law, we know that if the product of two numbers is 0 then either one or both of the numbers has to equal 0. In this case your 'numbers' are #6h - 5# and #6h + 5#
Therefore;
6h - 5 = 0
6h = 5
#h = 5/6#
and /or
6h + 5 = 0
6h = -5
#h = -5/6#