How do you solve #(6h-5)(6h+5)=0#?
Why do these come up in the feed if they're two years old?
From the null factor law, we know that if the product of two numbers is 0 then either one or both of the numbers has to equal 0. In this case your 'numbers' are
6h - 5 = 0
6h = 5
6h + 5 = 0
6h = -5