How do you solve #6m^2- 5m =1# by factoring? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Alan P. Aug 12, 2015 #m=-1/6# or #m=1# Explanation: Given #6m^2-5m = 1# #rArr##color(white)("XXXX")##6m^2-5m-1=0# Factoring the left side: #rArr##color(white)("XXXX")##(6m+1)(m-1)=0# #rArr##6m+1=0##color(white)("XXXX")#or#color(white)("XXXX")##m-1=0# #rArr##m=-1/6##color(white)("XXXXX")#or#color(white)("XXXX")##m=1# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1182 views around the world You can reuse this answer Creative Commons License