How do you solve 6n ^ { 0} \cdot n ^ { 0}?

Oct 27, 2017

Change ${n}^{0}$ to one and multiply

Explanation:

Any number to the zero power is equal to one. so

${n}^{0} = 1$

so substituting 1 for ${n}^{o}$ gives

$6 \times 1 \times 1 = 6$