How do you solve #6r^2+5r=-1# using the quadratic formula?

1 Answer
Apr 17, 2017

Answer:

#-6/12# and #-4/12#

Explanation:

Compute #Delta# first. #Delta=b^2-(4ac)# where a=6, b=5 and c=1 in the arranged equation: #6r^2+5r+1=0#

Now #Delta=1=5^2-(4*6*1)#

#sqrt Delta=1#

Now compute rs based on #r=(-b-sqrtDelta)/(2a)# and #r=(-b+sqrtDelta)/(2a)#

#r1=(-5-1)/(2*6)=-6/12# and #r2=(-5+1)/(2*6)=-4/12#

These are the answers: #-6/12# and #-4/12#