# How do you solve 6x^2=17x-12?

Jun 15, 2016

$\left(3 x - 4\right) \left(2 x - 3\right)$

#### Explanation:

As soon as you see an ${x}^{2}$ term, it is a quadratic equation and it has to be made equal to 0.

$6 {x}^{2} - 17 x + 12 = 0$

Find factors of 6 and 12 which add to 17.

We find factors of 6 and 12 and cross multiply
$3 \text{ } 4 \Rightarrow 2 \times 4 = 8$
$2 \text{ " 3 rArr 3 xx 3= 9 " } 8 + 9 = 17$

The signs in the brackets will be the same, (because of the + with the 12, they will both be -, (because of the sign with -17).

$\left(3 x - 4\right) \left(2 x - 3\right)$