# How do you solve #-6x - 2 = (3x + 1)^2#?

##### 1 Answer

#### Answer:

#### Explanation:

Let's start with the right-hand side. We can rewrite the equation as:

What I have in blue, we can multiply using the highly useful mnemonic **FOIL:**

- Multiply the
**first terms**,#3x# and#3x# to get#color(blue)(9x^2)# - Multiply the
**outside terms**,#3x# and#1# to get#color(blue)(3x)# - Multiply the
**inside terms**,#1# and#3x# to get#color(blue)(3x)# - Multiply the
**last terms**,#1# and#1# to get#color(blue)(1)#

After foiling the right side binomial, we have:

This is a quadratic equation, so we want to set it equal to zero to find its zeros.

Let's add

Now, we can factor by grouping. This is splitting up the

Notice,

We can factor a

**NOTE:** I was able to rewrite this as the product of two binomials because both terms had an

Now we can set our two binomials equal to zero. We get:

We can solve these equations to get:

Hope this helps!