How do you solve 6x^2+5x+1=0?

1 Answer
Jul 12, 2015

The solutions are:
color(blue)(x=-1/2,x=-1/3

Explanation:

6x^2 +5x+1 =0
We can first factorise the expression and then find the solutions.

Factorising by splitting the middle term

6x^2 +color(blue)(5x)+1 =0

6x^2 color(blue)(+2x +3x)+1 =0

2x(3x+1) +1(3x+1) =0

(2x+1)(3x+1) =0

Now we equate the factors with zero to obtain the solutions:

2x+1 =0, color(blue)(x=-1/2

3x+1=0, color(blue)(x=-1/3