How do you solve #6x^2 - x - 5 = 0 # using the quadratic formula?

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Answer 1 · 2015-08-10T07:15:40

The solutions for the equation are

#color(blue)(x=1, x=-5/6#

#6x^2−x−5=0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:
#a=6, b=-1, c=-5#

The Discriminant is given by:

#Delta=b^2-4*a*c#

# = (-1)^2-(4*6*(-5))#

#=1 +120#

#=121#

The solutions are found using the formula

#x=(-b+-sqrtDelta)/(2*a)#

#x = (-(-1)+-sqrt(121))/(2*6) = (1+-11)/12#

#x = -10/12, color(blue)(x=-5/6#

#x=12/12, color(blue)(x=1#