How do you solve #6x-2y=-4# and #y=3x+2#?

1 Answer
Aug 5, 2015

Answer:

There is an infinite number of solutions.

Explanation:

One way is to use the method of substitution.

Step 1. Enter the equations.

[1] #6x-2y=-4#
[2] #y=3x+2#

Step 2. Solve for one variable in terms of the other.

[2] #y=3x+2#

Since this is already done for us, we can go on to the next step.

Step 3. Substitute Equation 2 in Equation 1 and solve for #x#.

#6x-2(3x+2) =-4#

#6x-6x-4 = -4#

#-4=-4#

This indicates that the solution consists of all real numbers and the equations are identical.

We can see that the equations are identical if we solve Equation 1 for #y#.

#2y=6x+4#
#y=3x+2#

Some answers that fit are (#-1,-1#), (#0,2#), and (#1,5#).