How do you solve $-6x + 3= 2x - 1$ ?

Question

2619 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-20T07:02:08

$color(blue)(x = 1/2$

$-6x + 3 = 2x - 1$

$3 + 1 = 2x + 6x, " x terms to R H S & constant to L H S"$

$8x = 4$

$x = cancel(4)^color(red)(1) / cancel(8)^color(red)(2) = color(blue)(1/2$

How do you solve -6x + 3= 2x - 1-6x + 3= 2x - 1?