How do you solve #6x + 3 = -5x +14#?

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Answer 1 · 2018-05-21T16:02:58

See a solution process below:

First, subtract #color(red)(3)# and add #color(blue)(5x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#6x + color(blue)(5x) + 3 - color(red)(3) = -5x + color(blue)(5x) + 14 - color(red)(3)#

#(6 + color(blue)(5))x + 0 = 0 + 11#

#11x = 11#

Now, divide each side of the equation by #color(red)(11)# to solve for #x# while keeping the equation balanced:

#(11x)/color(red)(11) = 11/color(red)(11)#

#(color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11)) = 1#

#x = 1#

Answer 2 · 2018-05-21T16:11:48

#x=1#

#6x+3=-5x+14#

#:.6x+5x=14-3#

#:.11x=11#

#:.x=cancel 11^1/cancel 11^1#

#:.x=1#