How do you solve #6x-4y=10 # and #5x-7y=1#?
It can be solved by elimination method. To eliminate x, multiply the first equation by 5 and the second by 6 and then subtract as follows:
30x -42y =6
On subtraction it would be 22y= 44, that gives y=2. On substituting for y in the first equation it would be 6x=18, that gives x=3