How do you solve #-6x + 6= - 5x + 5#?
1 Answer
Apr 30, 2018
Explanation:
#"collect terms in x on one side of the equation and numeric"#
#"values on the other side"#
#"add "6x" to both sides"#
#cancel(-6x)cancel(+6x)+6=-5x+6x+5#
#rArr6=x+5#
#"subtract 5 from both sides"#
#6-5=xcancel(+5)cancel(-5)#
#rArr1=x" or "x=1#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left side "=-6+6=0#
#"right side "=-5+5=0#
#rArrx=1" is the solution"#