How do you solve #-6x + 6= - 5x + 5#?

1 Answer
Apr 30, 2018

#x=1#

Explanation:

#"collect terms in x on one side of the equation and numeric"#
#"values on the other side"#

#"add "6x" to both sides"#

#cancel(-6x)cancel(+6x)+6=-5x+6x+5#

#rArr6=x+5#

#"subtract 5 from both sides"#

#6-5=xcancel(+5)cancel(-5)#

#rArr1=x" or "x=1#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left side "=-6+6=0#

#"right side "=-5+5=0#

#rArrx=1" is the solution"#