How do you solve #-6y - 3 = 3 - 6y#?

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Answer 1 · 2017-06-01T19:26:10

See a solution process below:

First, add #color(red)(6y)# to each side of the equation:

#color(red)(6y) - 6y - 3 = 3 - 6y + color(red)(6y)#

#0 - 3 = 3 - 0#

#-3 != 3#

Because #-3# is not equal to #3# there is no solution to this equation. Or, the solution is the empty or null set: #{O/}#

Answer 2 · 2017-06-01T19:27:15

There is no solution to this equation and therefore

#x# has no value.

Re-arrange the equation with all the variables on one side and the numbers on the other side:

#-6y -3 = 3-6y#

#-6y +6y = 3+3#

#" "0 = 6" "larr?????????#

We have ended up with a statement that is obviously false and there is no variable.

This is an indication that the equation cannot be solved and there is no solution.

#x# has no value.