How do you solve #(6z - 5) = 0#?

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Answer 1 · 2017-05-13T14:13:17

See a solution process below:

First, remove the parenthesis, they are unnecessary:

#6z - 5 = 0#

Next, add #color(red)(5)# to each side of the equation to isolate the #z# term while keeping the equation balanced:

#6z - 5 + color(red)(5) = 0 + color(red)(5)#

#6z - 0 = 5#

#6z = 5#

Now, divide each side of the equation by #color(red)(6)# to solve for #z# while keeping the equation balanced:

#(6z)/color(red)(6) = 5/color(red)(6)#

#(color(red)(cancel(color(black)(6)))z)/cancel(color(red)(6)) = 5/6#

#z = 5/6#