How do you solve #7/15x+5/6=2/3x+3/5#?

Question

1553 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-11T18:01:50

#x = 7/6#

move the #x# values on one side, and the numbers on the other side

#7/15 x + 5/6 = 2/3 x + 3/5#

#7/15 x - 2/3 x# = #3/5 - 5/6#

#- 1/5 x = - 7/30#

#x = - 7/30 -:- 1/5#

#x = 7/6#

Answer 2 · 2018-04-11T19:09:59

#7/6#

#7/15+5/6=2/3x+3/5#

multiply both sides by #30#

#:.14x+25=20x+18#

#:.14x-20x=18-25#

#:.-6x=-7#

multiply both sides by #-1#

#:.6x=7#

#:.x=7/6#
~~~~~~~~~~~~~~

check:-

substitute #x=7/6#

#:.7/15(7/6)+5/6=2/3(7/6)+3/5#

#:.49/90+5/6=7/9+3/5#

multiply both sides by #90#

#:.49+75=70+54#

#:.124=124#