How do you solve #7(2+x)=35# using the distributive property?

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Answer 1 · 2017-02-20T20:26:06

#x=3#

Distribute the 7 into the parentheses. Note that the coefficient in front of the x is 1

#7 xx 2 = 14#

# 7 xx 1 = 7#

Your problem can be rewritten as:

#14+7x=35#

Now solve for x. Subtract 14 on both sides and then divide by 7:

#7x=21#

#x=3#

You can also do this dividing both sides of the equation in the beginning and simplifying:

#(7/7)(2+x)=35/7#

#2+x=5#

#x=3#