How do you solve #7(2x+1) = 3(x-5)#?

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Answer 1 · 2018-03-11T19:03:08

#-2#

#14x+7=3x-15#

#14x-3x=-15-7#

#11x=-22#

#x= (-22)/11#

#x=-2#

Answer 2 · 2018-03-11T19:04:31

#x=-2#

Our first step is to distribute the terms outside the parenthesis to the terms inside. Here, we are just multiplying. We get:

#14x+7=3x-15#

We can add #15# to both sides to get:

#14x+22=3x#

We can subtract #14x# from both sides to get:

#22=-11x#

We can divide both sides by #-11# to get:

#x=-2#