How do you solve #7( 2x - 1) = 5( x - 14)#?

3 Answers

Answer:

#x=-7#

Explanation:

Expand the brackets

#14x-7=5x-70#

Subtract #5x# from both sides

#9x-7=-70#

Add #7#to both sides

#9x=-63#

Divide both sides by #9#

#x=-7#

Mar 7, 2018

Answer:

#x=-7#

Explanation:

#7(2x-1)=5(x-14)#

Distribute and multiply #7# to #2x# and #-1# to get

#14x-7=#

Then distribute and multiply #5# to #x# and #-14# to get

#=5x-70#

Put together, it will look like this

#14x-7=5x-70#

Then add #70# to #-70# and #-7# to get

#14x+63=5x#

Then subtract #14x# from #14x# and #5x# to get

#63=-9x#

Divide by #-9# on both sides to get

#-7=x#

Mar 7, 2018

Answer:

See solution below:

Explanation:

First expand out the brackets:
#7(2x-1) = 14x -7#
and
#5(x-14) = 5x - 70#

Hence, the equation becomes:
#14x-7=5x-70#

Now rearrange to make #x# the subject:

  1. Subtract #5x# from both sides to obtain:
    #=> 14x-5x-7=5x-5x-70#
    #=> 9x-7=70#

  2. Then add 7 to both sides to isolate #x#
    #=> 9x-7+7=-70+7#
    #=> 9x = -63#

  3. Finally, divide both sides by 9 to obtain #x#
    #=> x=-63/9#

Hence,
#x=-7#