Question

How do you solve `7 * 3^t = 5 * 2^t`?

Answer 1

By using Log function

Explanation:

`7 * 3^t = 5 * 2 ^ t`
`log ( 7 * 3^t ) = log ( 5 * 2^t )`
`log(7)+log(3^t) = log(5)+log(2^t)`
`log(7)+tlog(3) = log(5)+tlog(2)`
`log(7)-log(5) = tlog(2)-tlog(3)`
`log(7/5)=t(log(2)-log(3))`
`log(7/5)=t(log(2/3))`
`log(7/5)/(log(2/3))=t`
then make good use of your cal.