How do you solve #7/3(x + 9/28) = 20#?

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Answer 1 · 2018-03-23T22:36:28

#x=-9/28+-sqrt(60/7) larr" Exact answer"#

The sub topic name chosen is quadratics!

So you must mean:

#7/3(x+9/28)^2=20#

Multiply both sides by #3/7#

#(x+9/28)^2=60/7#

Square root both sides

#x+9/28=+-sqrt(60/7)#

#x=-9/28+-sqrt(60/7) larr" Exact answer"#

Convert this into decimals and you will be rounding and thus introduce inaccuracies.