# How do you solve #7-3abs(4d-7)=4#?

##### 1 Answer

Aug 2, 2015

#### Explanation:

Your absolute value equation looks like this

Start by isolating the modulus on one side of the equation

Now, this equation will produce *two values* for

*If*#(4d-7)>0# ,*then you have*

#|4d-7| = 4d-7#

and the equation becomes

*If*#(4d-7)<0# ,*then you have*

#|4d-7| = -(4d-7) = -4d + 7#

This will get you