How do you solve #7(4 - 2x) + 16 + 2x = 12#?

1 Answer
Mar 24, 2015

Here you have an equation. First solve the brackets by multiplyinf #7# times the content of it:
#28-14x+16+2x=12#
Now collect all the #x#s on the left and the numbers on the right remembering to change sign when crossing the equal sign:
#-14x+2x=-28-16+12#
#-12x=-32#
Now get rid of the #-12# in front of the #x#: It is multiplying so it passes to the right dividing!
#x=-32/-12=8/3#